16-36y^2=0

Solution for 16-36y^2=0 equation:

16-36y^2=0

a = -36; b = 0; c = +16;
Δ = b2-4ac
Δ = 02-4·(-36)·16
Δ = 2304
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{2304}=48$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-48}{2*-36}=\frac{-48}{-72}
=2/3
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+48}{2*-36}=\frac{48}{-72}
=-2/3
$